Selina Concise Mathematics Class 10 ICSE Solutions Loci (Locus and Its Constructions) Selina Publishers Concise Mathematics Class 10 ICSE Solutions Chapter 16 Loci (Locus and Its Constructions) Locus and Its Constructions Exercise 16A – Selina Concise Mathematics Class 10 ICSE Solutions Question 1. Given— PQ is perpendicular bisector of side AB of the triangle ABC. Prove— Q is equidistant from A and B. Solution: Construction: Join AQ Proof: In ∆AQP and ∆BQP, AP = BP (given) ∠QPA = ∠QPB (Each = 90 ) PQ = PQ (Common) By Side-Angle-Side criterian of congruence, we have ∆AQP ≅ ∆BQP (SAS postulate) The corresponding parts of the triangle are congruent ∴ AQ = BQ (CPCT) Hence Q is equidistant from A and B. Question 2. Given— CP is bisector of angle C of ∆ ABC. Prove— P is equidistant from AC and BC. Solution: Question 3. Given— AX bisects angle BAG and PQ is perpendicular bisecto...
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