Selina Concise Mathematics Class 10 ICSE Solutions Chapter 6 - Solving Simple Problems (Based on Quadratic Equations)
Selina Concise Mathematics Class 10 ICSE Solutions Solving Simple Problems (Based on Quadratic Equations) Selina Publishers Concise Mathematics Class 10 ICSE Solutions Chapter 6 Solving Simple Problems (Based on Quadratic Equations) Solving Simple Problems (Based on Quadratic Equations) Exercise 6A – Selina Concise Mathematics Class 10 ICSE Solutions Question 1. The product of two consecutive integers is 56. Find the integers. Solution: Let the two consecutive integers be x and x + 1. From the given information, x(x + 1) = 56 x2 + x – 56 = 0 (x + 8) (x – 7) = 0 x = -8 or 7 Thus, the required integers are – 8 and -7; 7 and 8. Question 2. The sum of the squares of two consecutive natural numbers is 41. Find the numbers. Solution: Let the numbers be x and x + 1. From the given information, x2 + (x + 1)2 = 41 2x2 + 2x + 1 – 41 = 0 x2 + x – 20 = 0 (x + 5) (x – 4) = 0 x = -5, 4 But, -5 is not a natural number. So, x = 4. Thus, the numbers ...