Selina Concise Mathematics Class 6 ICSE Solutions Chapter 14 Fractions

Selina Concise Mathematics Class 6 ICSE Solutions – Fractions

Selina Concise Mathematics Class 6 ICSE Solutions – Fractions

EXERCISE 14(A)

Question 1.
For each expression, given below, write a fraction :
(i) 2 out of 7 = ………..
(ii) 5 out of 17 = ………..
(iii) three-fifths = ………
Solution:
(i) 2 out of 7 =
(ii) 5 out of 17 =
(iii) three-fifths =

Question 2.
Fill in the blanks :

Solution:
(i) Proper
(ii) Improper
(iii) Improper
(iv) 1
(v) -1
(vi) Mixed
(vii) Like
(viii) Unlike fraction
(ix) Equal fraction
(x) Like

Question 3.
From the following fractions, separate :
(i) Proper fractions
(ii)Improper fractions :

Solution:

We know that proper fraction is a fraction whose numerator is less than its denominator and improper fraction is the fraction whose numerator is greater them its denominator :

Question 4.
Change the following mixed fractions to improper fractions :

Solution:

Question 5.
Change the following improper fractions to mixed fractions :

Solution:

Question 6.
Change the following groups of fractions to like fractions :

Solution:

EXERCISE 14(B)

Question 1.
Reduce the given fractions to their lowest terms :

Solution:

Question 2.
State, whether true or false ?

Solution:

Question 3.
Which fraction is greater ?

Solution:

Question 4.
Which fraction is smaller ?

Solution:

Question 5.
Arrange the given fractions in descending order of magnitude :

Solution:

Question 6.
Arrange the given fractions in ascending order of magnitude :

 
Solution:

Question 7.

I bought one dozen bananas and ate five of them. What fraction of the total number of bananas was left ?

Solution:

Number of bananas bought = 1
Dozen = 12
Number of bananas eaten by me = 5
Number of bananas left = 12 – 5 = 7
Fraction =

Question 8.
Insert the symbol ‘=’ or ‘>’ or ‘<’ between each of the pairs of fractions, given below :

Solution:

Question 9.
Out of 50 identical articles, 36 are broken. Find the fraction of :
(i) The total number of articles and the articles broken.
(ii) The remaining articles and total number of articles.
Solution:
Total number of articles = 50
Number of articles broken = 36
Remaining articles = 50 – 36 = 14
Now (i) the fraction of the total number of articles and articles broken =

 

EXERCISE 14(C)

Question 1.
Add the following fractions :

Solution:

Question 2.
Simplify :

 
Solution:

EXERCISE 14(D)

Point to Remember :
BODMAS :- While simplifying an expressions we can involve six operation in following orders.
B Stands for “BRACKET”
O Stands for “OF”
D Stands for “DIVISION”
M Stands for “MULTIPLICATION”
A Stands for “ADDITION”
S Stands for “SUBTRACTION”

Question 1.
Simplify :

Solution:

  
Question 2.
Simplify :

Solution:

Question 3.
Simplify :

Solution:

Question 4.
Simplify :

Solution:

Question 5.
Simplify :

Solution:

 

EXERCISE 14(E)

Question 1.
From a rope of 10m long, 4m is cut off. Find the length of the remaining rope.
Solution:

Question 2.

A piece of cloth is 5 metre long. After washing, it shrinks byof its length. What is the length of the cloth after washing ?

Solution:

Question 3.

I bought wheat worth Rs. 12, rice worth Rs. 25and vegetables worth

Rs. 10. If I gave a hundred-rupee note to the shopkeeper ; how much did he return to me

Solution:

Question 4.

Out of 500 oranges in a box,are rotten andare kept for some guests. How many oranges are left in the box?

Solution:

Question 5.

An ornament piece is made of gold and copper. Its total weight is 96g. Ifof the ornament hi copper, find the weight of gold in it.

Solution:

Question 6.

A girl did half of some work on Monday and one-third of it on Tuesday. How much will she have to do on Wednesday in order to complete the work ?

Solution:

Question 7.

A man spendsof his money and 8 still has Rs. 720 left with him. How much money did he have at first ?

Solution:

Question 8.

In a school,of the students are boys, and the number of girls is 100. Find the number of boys.

Solution:

Question 9.

After finishingof my journey, I find that 12 km of my journey is covered. How much distance is still left to be covered ?

Solution:

Question 10.

When Ajit travelled 15 km, he found that one-fourth of his journey was still left. What was the full length of the journey ?

Solution:

 
Question 11.

In a particular month, a man earns Rs. 7,200. Out of this income, he spendson food,  on house rent,on insurance andon holidays. How much did he save in that month ?

Solution:

REVISION EXERCISE

Question 1.

Solution:

Question 2.

Solution:

Question 3.
Evaluate :

Solution:

Question 4.

Mr. Mehra gave one-third of his money to his son, one-fifth of his money to his daughter and the remaining amount to his wife. If his wife got Rs. 91,000, how much money did Mr. Mehra have originally?

Solution:

Question 5.
A sum of Rs. 84,000 is divided among three persons A, B and C. If A gets one-fourth of it and B gets one-fifth of it; how much did C get ?
Solution:

= Rs. 84,000 – (37,800) = Rs. 46,200

Question 6.
In one hour Rohit walks 3km. How much distance will he cover in 2hours?

Solution:

 
Question 7.

An 84 m long string is cut into pieces each of length 5m. How many pieces are obtained ?

Solution:

Question 8.

In buying a ready made shirt-two-fifths of my pocket money is spent If Rs. 540 is still left with me, find :

(i) The money I had before I bought the shirt.

(ii) The emit of the shirt
Solution:

Question 9.

Mohan leaves Rs. 1,20,000 to his wife and three children such that two-fifths of this money is given to his wife and the remaining is distributed equally among the children. Find, how much each child gets ?

Solution:

Total amount = Rs. 12,0,000
Amount given to his wife =of Rs. 1,20,000
= Rs. 2 x 24,000 = Rs. 48,000
Remaining amount = Rs. 120000 – Rs. 48000 = Rs. 72000
This amount is distributed among three children equally.
Each’s share = Rs. 72,000 x= Rs. 24,000

Question 10.
Simplify :

Solution: