Selina Concise Mathematics Class 9 ICSE Solutions Indices (Exponents)
Selina ICSE Solutions for Class 9 Maths Chapter 7 Indices (Exponents)
Exercise 7(A)1.Evaluate:
(i)
(ii)
(iii)
(iv)
(v)
Solution 1:
2.Simplify:
(i)
(ii)
(iii)
(iv)
Solution 2:
3.Evaluate:
(i)
(ii)
Solution 3:
4.Simplify each of the following and express with positive index:
(i)
(ii)
(iii)
(iv)
Solution 4:
5.If 2160 = 2a. 3b. 5c, find a, b and c. Hence calculate the value of 3a 2-b 5-c.
Solution 5:
6.If 1960 = 2a. 5b. 7c, calculate the value of 2-a. 7b. 5-c.
Solution 6:
7.Simplify:
(i)
(ii)
Solution 7:
8.Show that:
Solution 8:
9.If a = xm + n. yl; b = xn + l. l . ym and c = xl + m. yn,
Prove that: am - n. bn - l. cl - m = 1
Solution 9:
10.Simplify:
(i)
(ii)
Solution 10:
Exercise 7(B)
1.Solve for x:
(i) 22x+1 = 8
(ii) 25x-1 = 4 23x + 1
(iii) 34x + 1 = (27)x + 1
(iv) (49)x + 4 = 72 (343)x + 1
Solution 1:
2.Find x, if:
(i)
(ii)
(iii)
(iv)
Solution 2:
3.Solve:
(i) 4x - 2 - 2x + 1 = 0
(ii)
Solution 3:
4.Solve :
(i) 8 22x + 4 2x+1 = 1 + 2x
(ii)22x + 2x+2 - 4 23 = 0
(iii)
Solution 4:
5.Find the values of m and n if:
Solution 5:
6.
Solution 6:
7.Prove that:
(i) =1
(ii)
Solution 7:
8.If ax = b, by = c and cz = a, prove that: xyz = 1.
Solution 8:
9.If ax = by = cz and b2 = ac, prove that :.
Solution 9:
10.If 5-P = 4-q = 20r, show that:
Solution 10:
11.If m ≠ n and (m + n)-1 (m-1 + n-1) = mxny, show that:
x + y + 2 = 0
Solution 11:
12.If 5x + 1 = 25x - 2, find the value of
3x - 3 × 23 - x
Solution 12:
13.If 4x + 3 = 112 + 8 × 4x, find the value of (18x)3x.
Solution 13:
14.(i)Solve for x:
4x-1 × (0.5)3 - 2x =
Solution 14(i):
14.(ii)Solve for x:
(a3x + 5)2. (ax)4 = a8x + 12
Solution 14(ii):
14.(iii)Solve for x:
Solution 14(iii):
14.(iv)Solve for x:
23x + 3 = 23x + 1 + 48
Solution 14(iv):
14.(v)Solve for x:
3(2x + 1) - 2x + 2 + 5 = 0
Solution 14(v):
Exercise 7(C)
1.
Solution 1:
2.
Solution 2:
3.Solve: 3x-1× 52y-3 = 225.
Solution 3:
4.
Solution 4:
5.If 3x+1 = 9x-3, find the value of 21+x.
Solution 5:
6.
Solution 6:
7.
8.
Solution 8:
9.
Solution 9:
10.Solve: 3(2x + 1) - 2x+2 + 5 = 0.
11.If (am)n = am .an, find the value of:
m(n - 1) - (n - 1)
Solution 11:
12.
Solution 12: