Selina Concise Mathematics Class 9 ICSE Solutions Complementary Angles
Selina ICSE Solutions for Class 9 Maths Chapter 25 Complementary Angles
Exercise 25(A)1.(i)
Solution 1(i):
1.(ii)
Solution 1(ii):
1.(iii)
Solution 1(iii):
1.(iv)
Solution 1(iv):
1.(v)
Solution 1(v):
1.(vi)
Solution 1(vi):
1.(vii)
Solution 1(vii):
1.(viii)
Solution 1(viii):
2.(i)
Solution 2(i):
2.(ii)
Solution 2(ii):
2.(iii)
Solution 2(iii):
2.(iv)
Solution 2(iv):
2.(v)
Solution 2(v):
2.(vi)
Solution 2(vi):
3.(i)Show that:
tan 10° tan 15° tan 75° tan 80° = 1
Solution 3(i):
3.(ii)Show that:
sin 42° sec 48° + cos 42° cosec 48° = 2
4.Express each of the following in terms of angles between 0°and 45°:
(i) sin 59°+ tan 63°
(ii) cosec 68°+ cot 72°
(iii)cos 74°+ sec 67°
Solution 4:
5.For triangle ABC, show that:
(i) 
(ii) 
Solution 5:
6.Evaluate:
(i) 
(iii) 
(iv) 
(v) 
(vi) 
(vii) 
(viii) 
(ix) 
Solution 6:
7.
Solution 7:
8.(i)In each case, given below, find the value of angle A, where 0° ≤ A ≤ 90°.
sin (90° - 3A).cosec 42° = 1
Solution 8(i):
8.(ii)In each case, given below, find the value of angle A, where 0° ≤ A ≤ 90°.
cos (90° - A).sec 77° = 1
Solution 8(ii):
Selina Concise Mathematics Class 9 ICSE Maths Solutions Chapter 25 - Complementary Angles