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Selina ICSE Solutions for Class 9 Physics Chapter 7 Reflection of Light

Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

Exercise 7(A)

1S.What do you mean by reflection of light? 

Solution 1S.

The return of light into the same medium after striking a surface is called reflection.

2S.State which surface of a plane mirror reflects most of the light incident on it: the front smooth surface or the back silvered surface. 

Solution 2S.

Black silvered surface reflects most of the light incident on it.

3S.Explain the following terms:

(a) Plane mirror,  (b) Incident ray,
(c) Reflected ray,  (d) Angle of incidence and
(e) Angle of reflection.

Draw diagram/diagrams to show them. 

Solution 3S.

(a) Plane mirror: Plane mirror is a highly polished and smooth reflecting surface made from a clear plane glass sheet, usually thin and silvered with suitable reflecting abrasive (for example, mercury) on one side. Once this pasting is done, then the glass becomes opaque but due to the reflecting property of the abrasive, the plane glass sheet becomes a plane glass reflector or a plane glass mirror.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

(b) Incident ray: The light ray striking a reflecting surface is called the incident ray.
(c) Reflected ray: The light ray obtained after reflection from the surface, in the same medium in which the incident ray is travelling, is called the reflected ray.
(d) Angle of incidence: The angle which the incident ray makes with the normal at the point of incidence is called the angle of incidence. It is denoted by the letter i.
(e) Angle of reflection: The angle which the reflected ray makes with the normal at the point of incidence is called the angle of reflection. It is denoted by the letter r.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

4S.With the help of diagrams, explain the difference between the regular and irregular reflection. 

Solution 4S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

Regular reflection occurs when a beam of light falls on a smooth and polished surface and irregular reflection occurs when a beam of light falls on a rough surface. Since the surface is uneven, from different points light rays get reflected in different directions and give rise to irregular reflection.

5S.Differentiate between the reflection of light from a plane mirror and that from a plane sheet of paper.

Solution 5S.

Reflection of light from a plane mirror is regular reflection and reflection of light from plane sheet of paper is irregular reflection of light.

6S.State the two laws of reflection of light.

Solution 6S.

Laws of reflection:
The angle of incidence is equal to the angle of reflection.
The incident ray, the reflected ray and the normal at the point of incidence, lie in the same plane.

7S.State the laws of reflection of light and describe an experiment to verify it.

Solution 7S.

Laws of reflection:
  1. The angle of incidence is equal to the angle of reflection.
  2. The incident ray, the reflected ray and the normal at the point of incidence, lie in the same plane.
Experiment to verify the laws of reflection:

Fix a white sheet of paper on a drawing board and draw a line MM1 as shown in figure. On this line, take a point O nearly at the middle of it and draw a line OA such that ∠MOA is less than 90o. Then draw a normal ON on line MM1 at the point O, and place a small plane mirror vertical by means of a stand with its silvered surface along MM1.

Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

Next fix two pins P and Q at some distance (≈5 cm) apart vertically on line OA, on the board. Keeping eye on the other side of normal (but on the same side of mirror), see clearly images P’ and Q’ of the pins P and Q. Next fix a pin R such that it is in line with the images of pins P and Q as observed in the mirror. Next, fix one more pin S such that the pin S is in line with the pin R as well as images P’ and Q’ of pins P and Q.
Draw small circles on paper around the positions of pins as shown in figure. Remove the pins and draw a line OB joining the pin points S and R, which meets the surface of mirror at O. The angles AON and BON are measured and recorded.
The experiment is then repeated for the angle of incidence ∠AON equal to 40o, 50o, 60o.
From results, it is observed that angle of incidence is equal to the angle of reflection. This verifies the first law of reflection.
The experiment has been performed on a flat drawing board, with mirror normal to the plane of board on which white sheet of paper is being fixed. Since the lower tips of all the pins also lie on the same plane (i.e., the plane of paper), it proves the second law of reflection.

8S.A light ray is incident normally on a plane mirror. (a) What is its angle of incidence?
(b) What is the direction of reflected ray? Show it on a diagram.

Solution 8S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

9S.Draw a diagram to show the reflection of a ray of light using a plane mirror. In the diagram, label the incident ray, the reflected ray, the normal, the angle of incidence and the angle of reflection.

Solution 9S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

10S.Fig. shows an incident ray AO and the normal ON on a plane mirror. The angle which the incident ray AO makes with mirror is 30Selina Solutions Icse Class 9 Physics Chapter - Reflection Of Light (a) Find the angle of incidence. (b) Draw the reflected ray and then find the angle between the incident and reflected rays.

Solution 10S.

(a) Angle of incidence = 90o – 30o = 60o
(b) Angle between the incident ray and reflected ray = Angle of incidence + Angle of reflection
Angle of reflection = Angle of incidence = 60o
Therefore, Angle between the incident ray and reflected ray = 60o + 60o = 120o
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

11S.he diagram in Fig. shows a point object P in front of a plane mirror MM1.

(a) Complete the diagram by taking two rays from the point P to show the formation of its image.

Selina Solutions Icse Class 9 Physics Chapter - Reflection Of Light

(b) In the diagram, mark the position of eye to see the image.
(c) Is the image formed real or virtual? Explain why?


Solution 11S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

12S.The diagram below in Fig. shows an object XY in front of a plane mirror. Draw on the diagram, the image of the object formed by the mirror. Trace the path of two rays from a point on the object to show the formation of image.

Selina Solutions Icse Class 9 Physics Chapter - Reflection Of Light








Solution 12S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

13S.(a) Write three characteristics of the image formed by a plane mirror?

(b) How is the position of an image related to the position of the object? 

Solution 13S.

(a) Three characteristics of image formed by plane mirror:
  1. Image formed in erect (upright)
  2. Image formed is virtual
  3. Image formed is of the same size as the object

(b) The image is situated at the same perpendicular distance behind the mirror as the object in front of it.

14S.Differentiate between a real and a virtual image. 

Solution 14S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

15S.What is meant by lateral inversion of an image in a plane mirror? Explain it with the help of a ray diagram. 

Solution 15S.

The interchange of the left and right sides in the image of an object in a plane mirror is called lateral inversion.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

Figure above shows the image formation of a letter P in a plane mirror.

16S.The letters on the front of an ambulance are written laterally inverted like Selina Solutions Icse Class 9 Physics Chapter - Reflection Of LightGive reason.

Solution 16S.

The letters on the front of a ambulance are written laterally inverted, so that the driver of the vehicle moving ahead of the ambulance reads these words laterally inverted as AMBULANCE, in his rear view mirror, and gices side to pass the ambulance first.

17S.Why is it difficult to read the image of the text of a page formed due to reflection by a plane mirror? 

Solution 17S.

Due to lateral inversion, , it becomes difficult to read the image of the text of a page formed due to reflection by a plane mirror.

1M.According to the law of reflection:

(a) i/r = constant
(b) sin i /sin r = constant
(c) i + r = constant
(d) i = r 

Solution 1M.

i = r

2M.The image formed by a plane mirror has the following characteristic:

(a) Erect and diminished
(b) Erect and enlarged
(c) Inverted and of same size
(d) Erect and of same size. 

Solution 2M.

Erect and of same size

3M.The image formed by a plane mirror is :

(a) real
(b) virtual
(c) virtual with lateral inversion
(d) real with lateral inversion

Solution 3M.

virtual with lateral inversion

1N.The incident ray and the reflected ray from a mirror are mutually perpendicular to each other. Find the angle of incidence. 

Solution 1N.

Angle of incidence (i) + Angle of reflection(r) = 90o
But, as per the laws of reflection, i = r
Therefore, 2 i = 90o
Or, i = r = 45o

2N.A man standing in front of a plane mirror finds his image at a distance 6 metre from himself. What is the distance of man from the mirror? 

Solution 2N.

Distance between man and his image = 6m
Distance between man and mirror + distance between mirror and image = 6m
But, Distance between man and mirror (object distance) = distance between mirror and image (image distance)
Therefore, distance of man from mirror = 6/2 = 3m

3N.An insect is sitting in front of a plane mirror at a distance 1 m from it.

(a) Where is the image of the insect formed? (b) What is the distance between the insect and its image?

Solution 3N.

(a) Image of the insect is formed 1m behind the mirror.
(b) Distance between the insect and his image = 1 + 1 = 2 m

4N.An object is kept at 60 cm in front of a plane mirror. If the mirror is now moved 25 cm away from the object, how does the image shift from its previous position? 

Solution 4N.

Initially, distance of the object from the mirror = 60 cm.
Therefore, image is formed at a distance 60 cm from the mirror, behind it.
Thus, initial distance between the object and image = 60 + 60 = 120 cm
If the mirror is moved 25 cm away from the object,
The new distance of the object from the mirror = 60 + 25 = 85 cm
The new image is now at a distance 85 cm from the mirror behind it.
Thus, new distance of the image from the object = 85 + 85 = 170 cm
Taking the position of the object as reference point, the distance between the two positions of the image = new distance of image from the object – initial distance of the image from the object
= (170 – 120) cm = 50 cm
Thus, the image shifts 50 cm away.

5N.An optician while testing the eyes of a patient keeps a chart of letters 3 m behind the patient and asks him to see the letters on the image of chart formed in a plane mirror kept at distance 2 m in front of him. How far away is the chart seen by the patient? 

Solution 5N.

Distance between man and chart = 3m
Distance between man and mirror = 2m
Therefore, distance between chart and mirror = 5 m
Now, final image is formed on the mirror, which is at a distance of 2 m from the man, therefore, the chart as seen by patient is (5m + 2m =) 7m away.

Exercise 7(B)

1S.Two plane mirrors are placed making an angle Selina Solutions Icse Class 9 Physics Chapter - Reflection Of Lightin between them. Write an expression for the number of images formed of an object placed in between the mirrors. State the condition, if any. 

Solution 1S.

If two mirrors make an angle θ with each other and object is placed in between the two mirrors, the number of images formed is n or (n – 1) depending upon n = 360o / θo is odd or even.
(a) If n = 360o / θo is odd,
(i) The number of images formed is n, when the object is placed asymmetrically between the mirrors.
(ii) The number of images formed is n-1, when the object is placed symmetrically between the mirrors.
(b) If n = 360o / θo is even, the number of images is always n-1.

2S.Two plane mirrors are placed making an angle θ° in between them. For an object placed in between the mirrors, if angle is gradually increased from 0 to 180, how will the number of images change: increase, decrease or remain unchanged?

Solution 2S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

3S.How many images are formed for a point object kept in between two plane mirrors M1 and M2 at right angles to each other? Show them by drawing a ray diagram. 

Solution 3S.

For two mirrors kept perpendicular to each other, three images are formed for an object kept in between them.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

4S.Two plane mirrors are arranged parallel and facing each other at some separation. How many images are formed for a point object kept in between them? Show the formation of images with the help of a ray diagram 

Solution 4S.

For two mirrors kept parallel to each other, an infinite number of images are formed for an object kept in between them.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

5S.State two uses of a plane mirror. 

Solution 5S.

Two uses of plane mirror:
In barber’s shop for seeing the hairs at the back of head, two mirrors facing each other are fixed on opposite walls at the front and back of the viewer.
In solar heating devices such as a solar cooker, solar water heater, etc., a plane mirror is used to reflect the incident light rays from sun on the substance to be heated.

1M.Two plane mirrors are placed making an angle 60Selina Solutions Icse Class 9 Physics Chapter - Reflection Of Light in between them. For an object placed in between the mirrors, the number of images formed will be :

(a) 3  (b) 6
(c) 5  (d) infinite.

Solution 1M.

5

2M.In the barber's shop, two plane mirrors are placed:

a. Perpendicular to earth other
b. Parallel to each other
c. At an angle 60° between them
d. At angle 45° between them

Solution 2M.

In a barber’s shop, two plane mirrors are placed parallel to each other.

1N.State the number of images of an object placed between two mirrors, formed in each case when mirrors are inclined to each other at (a) 90°, and (b) 60°.

Solution 1N.

(a) Angle between the mirrors, θ = 90o
Now, n = 360o / θo = 360o / 90o = 4, which is even.
Hence number of images formed will be (n-1); i.e., 4-1 = 3 images
(b) Angle between the mirrors, θ = 60o
Now, n = 360o / θo = 360o / 60o = 6, which is even.
Hence number of images formed will be (n-1); i.e., 6-1 = 5 images

2N.An object is placed (i) asymmetrically (ii) symmetrically, between two plane mirrors inclined at an angle of 50Selina Solutions Icse Class 9 Physics Chapter - Reflection Of Light. Find the number of images formed.

Solution 2N.

Angle between the mirrors, θ = 50o
Now, n = 360o / θo = 360o / 50o = 7.2  7, which is odd.
(i) When placed asymmetrically, number of images formed will be n, i.e. 7.
(ii) When placed symmetrically, number of images formed will be (n-1); i.e. 7-1 = 6 images

Exercise 7(C)

1S.What is a spherical mirror? 

Solution 1S.

A reflecting surface which is a part of a sphere is called a spherical mirror.

2S.Name the two kinds of spherical mirrors and distinguish between them. 

Solution 2S.

Two kinds of spherical mirrors are concave and convex.
Distinction between concave and convex mirror: A concave mirror’s bulging surface is silvered and reflection takes place from the hollow surface but a convex mirror’s inner surface is silvered and reflection takes place from the bulging surface.

3S.Define the terms pole, principal axis and centre of curvature with reference to a spherical mirror.

Solution 3S.

Pole: The geometric centre of the spherical surface of mirror is called the pole of mirror.
Principal axis: It is the straight line joining the pole of the mirror to its centre of curvature.
Centre of curvature: The centre of curvature of a mirror is the centre of the sphere of which the mirror is a part.

4S.Draw suitable diagrams to illustrate the action of (i) concave mirror and (ii) convex mirror on a beam of light incident parallel to the principal axis. 

Solution 4S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

5S.Name the spherical mirror which (i) diverges (ii) converges the beam of light incident on it. Justify your answer by drawing a ray diagram in each case. 

Solution 5S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

6S.Define the terms focus and focal length of a concave mirror. Draw diagram to illustrate your answer. 

Solution 6S.

Focus of a concave mirror: The focus of a concave mirror is a point on the principal axis through which the light rays incident parallel to principal axis, pass after reflection from the mirror.
Focal length of a concave mirror: The distance of the focus from the pole of the concave mirror is called its focal length.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

7S.Explain the meaning of the terms focus and focal length in case of a convex mirror, with the help of suitable ray diagram. 

Solution 7S.

Focus of a convex mirror: The focus of a convex mirror is a point on the principal axis from which, the light rays incident parallel to principal axis, appear to come, after reflection from the mirror.
Focal length of a convex mirror: The distance of the focus from the pole of the convex mirror is called its focal length.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

8S.State the direction of incident ray which after reflection from a spherical mirror retraces its path. Give a reason to your answer. 

Solution 8S.

Incident ray is directed towards the centre of curvature because the ray is normal to the spherical mirror, so ∠i = ∠r = O.

9S.(i) Name the mirrors shown in Fig. (a) and (b).

 (ii) In each case (a) and (b), draw reflected rays for the given incident rays and mark focus by the symbol F.

Selina Solutions Icse Class 9 Physics Chapter - Reflection Of Light
 (a) (b)

Solution 9S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

10S.Complete the following diagrams in Fig. by drawing the reflected rays for the incident rays 1 and 2.

Selina Solutions Icse Class 9 Physics Chapter - Reflection Of Light

Solution 10S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

11S.Complete the following diagrams shown in Fig. by drawing the reflected ray for each of the incident ray A and B.

Selina Solutions Icse Class 9 Physics Chapter - Reflection Of Light









Solution 11S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

12S.State the two convenient rays that are chosen to construct the image by a spherical mirror for a given object? Explain your answer with the help of suitable ray diagrams.

Solution 12S.

Two convenient rays that are chosen to construct the image by a spherical mirror for a given object:


1. A ray passing through the centre of curvature: A ray of light passing through the centre of curvature of a concave mirror or a ray directed in the direction of centre of curvature of a convex mirror is reflected back along the same path after reflection.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

2. A ray parallel to the principal axis: A ray of light parallel to the principal axis, after reflection pass through the principal focus in case of a concave mirror or appears to diverge from it in case of convex mirror.

Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

13S.Fig. shows a concave mirror with its pole at P, focus F and centre of curvature C. Draw ray diagram to show the formation of image of an object OA.


Selina Solutions Icse Class 9 Physics Chapter - Reflection Of Light










Solution 13S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

14S.Fig. shows a concave mirror with its pole at P, focus F and centre of curvature C. Draw ray diagram to show the formation of image of an object OA.

Selina Solutions Icse Class 9 Physics Chapter - Reflection Of Light











Solution 14S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

15S.Draw a ray diagram to show the formation of image by a concave mirror for an object placed between its pole and focus. State three characteristics of the image.

Solution 15S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

The image formed is virtual, erect and magnified.

16S.

Solution 16S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

The image formed is real, inverted and magnified.

17S.Draw a ray diagram to show the formation of image of an object kept in front of a convex mirror. State three characteristics of the image. 

Solution 17S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

The image formed is virtual, erect and diminished.

18S.Name the mirror which always produces an erect and virtual image. How is the size of image related to the size of object? 

Solution 18S.

Convex mirror always produces erect and virtual images. The images formed are diminished, i.e. the size of the image is shorter than the size of the object.

19S.(a) For what position of object, the image formed by a concave mirror is magnified and erect?
(b) State whether the image in part (a) is real or virtual? 

Solution 19S.

(a) If the object is placed between the pole and focus of a concave mirror, the image formed is magnified and erect.
(b) The image is virtual.

20S.(a) State the position of object for which the image formed by a concave mirror is of same size.

(b) Write two more characteristics of the image. 

Solution 20S.

(a) If the object is placed at the centre of curvature of a concave mirror, the image formed is of same size.
(b) The image formed is real and inverted.

21S.(a) What is a real image?

(b) What type of mirror can be used to obtain a real image of an object?

(c) Does the mirror mentioned in part (b) form real image for all locations of the object? 

Solution 21S.

(a) An image which can be obtained on a screen is called a real image.
(b) A concave mirror can be used to obtain a real image of an object.
(c) No, it does not form real image for all locations of the object.

22S.Discuss the position and nature of image formed by a concave mirror when an object is moved from infinity towards the pole of mirror. 

Solution 22S.

When an object is moved from infinity towards the pole of mirror, the image formed moves away from the mirror. The image formed is real and inverted.

23S.Discuss the position and nature of image formed by a convex mirror when an object is moved from infinity towards the pole of mirror. 

Solution 23S.

In a convex mirror, the image formed is always virtual, upright and diminished. It is always situated between its pole and focus, irrespective of the distance of object in front of the mirror.

24S.Name the kind of mirror used to obtain:

(a) A real and enlarged image,

(b) A virtual and enlarged image,

(c) A virtual and diminished image,

(d) A real and diminished image. 

Solution 24S.

(a) Concave, (b) Concave, (c) Convex and (d) Concave

25S.How is the focal length of a spherical mirror related to its radius of curvature?

Solution 25S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

26S.Write the spherical mirror's formula and explain the meaning of each symbol used in it.

Solution 26S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

27S.What is meant by magnification? Write its expression. What is its sign for the (a) real (b) virtual, image?

Solution 27S.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

28S.At what maximum distance the image in a convex mirror can be obtained? What will be the location of object then?

Solution 28S.

The image formed by a convex mirror is always between pole and focus. Hence, the maximum distance that can be obtained in convex mirror is the focal length. For this case the object has to be at infinity.

29S.At what maximum distance from a concave mirror, the image can be obtained? What will be the location of object for it?

Solution 29S.

The maximum distance that can be obtained in concave mirror is infinity. For this case the object has to be at focus.

30S.How will you distinguish between a plane mirror, a concave mirror and a convex mirror, without touching them? 

Solution 30S.

To distinguish between a plane mirror, concave mirror and convex mirror, the given mirror is held near the face and image is seen. There can be following three cases:
Case (i): If the image is upright, of same size and it does not change in size by moving the mirror towards or away from the face, the mirror is plane.
(ii) If the image is upright and magnified, and increases in size on moving the mirror away, the mirror is concave.
(iii) If the image is upright and diminished and decreases in size on moving the mirror away, the mirror is convex.

31S.State two uses of a concave mirror. 

Solution 31S.

Two uses of concave mirror:
It is used as a shaving mirror.
It is used as reflector in torch, head light of automobiles etc.

32S.State the kind of mirror used

(a) By a dentist,

(b) As a search-light reflector. 

Solution 32S.

(a) Concave mirror
(b) Concave mirror

33S.(a) When a concave mirror is used as a shaving mirror, where is the person's face in relation to the focus of mirror?

(b) State three characteristics of the image seen in part (a). 

Solution 33S.

(a) The person’s face is between the pole and focus of the mirror.
(b) The image formed is erect, virtual and magnified.

34S.Which mirror will you prefer to use as a rear view mirror in a truck: plane mirror or convex mirror? Give one reason. 

Solution 34S.

A convex mirror is preferred as a rear view mirror because it has a wider field of view as compared to a plane mirror of same size.

35S.Why does a driver use a convex mirror as a rear view mirror? Illustrate your answer with the help of a ray diagram. 

Solution 35S.

A convex mirror diverges the incident beam and always forms a virtual, small and erect image between its pole and focus. Thus, a driver can see all the traffic approaching from behind. This fact enables the driver to use it as a rear view in vehicles to see all the traffic approaching from behind.

Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

1M.For an incident ray directed towards centre of curvature of a spherical mirror the reflected ray:

(a) Retraces its path

(b) Passes through the focus

(c) Passes through the pole

(d) Becomes parallel to the principal axis. 

Solution 1M.

Retraces its path

2M.The image formed by a convex mirror is 

(a) Erect and diminished.

(b) Erect and enlarged.

(c) Inverted and diminished.

(d) Inverted and enlarged. 

Solution 2M.

Erect and diminished

3M.A real and enlarged image can be obtained by using a

(a) Convex mirror  

(b) Plane mirror

(c) Concave mirror

(d) Either convex or plane mirror. 

Solution 3M.

Concave mirror

1N.The radius of curvature of a convex mirror is 40 cm. Find its focal length. 

Solution 1N.

Focal length = ½ (Radius of curvature)
Or, f = 40/2 = 20 cm

2N.The focal length of a concave mirror is 10 cm. Find its radius of curvature. 

Solution 2N.

Radius of curvature = 2 x focal length
Or, R = 2f = 2 x 10 = 20 cm

3N.An object of height 2 cm is placed at a distance 20 cm in front of a concave mirror of focal length 12 cm. Find the position, size and nature of the image by drawing. 

Solution 3N.

Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

The image is 30 cm in front of the mirror, 3 cm high, real, inverted and magnified.

4N.An object is placed at 4 cm distance in front of a concave mirror of radius of curvature 24 cm. Find the position of image by drawing. Is the image magnified? 

Solution 4N.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

The image is 6 cm behind the mirror.
Yes the image is magnified.

5N.At what distance from a concave mirror of focal length 25 cm should an object be placed so that the size of image is equal to the size of the object. Draw a ray diagram to show this. 

Solution 5N.

The size of the image is equal to the size of the object if the object is placed at the centre of curvature of a concave mirror.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

Hence, the object should be placed at 50 cm.

6N.An object 5 cm high is placed at a distance 60 cm in front of a concave mirror of focal length 10 cm. Find the position and size of the image by drawing. 

Solution 6N.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

The position of the object is 12 cm in front of the mirror.
Its size is 1 cm.

7N.A point light source is kept in front of a convex mirror at a distance of 40 cm. The focal length of the mirror is 40 cm. Find the position of image by drawing. 

Solution 7N.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

8N.When an object of height 1 cm is kept at a distance 4 cm from a concave mirror, its erect image of height 1.5 cm is formed at a distance 6 cm behind the mirror. Find the focal length of mirror, by drawing. 

Solution 8N.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

A ray passing parallel to the principal axis passes through the focal point after reflection. Hence, the focal length is 12 cm.

9N.An object of length 4 cm is placed in front of a concave mirror at distance 30 cm. The focal length of mirror is 15 cm.

a. Where will the image form?

b. What will be the length of image?

Solution 9N.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

10N.A concave mirror forms a real image of an object placed in front of it at a distance 30 cm, of size three times the size of object. Find (a) the focal length of mirror (b) position of image.

Solution 10N.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

11N.A concave mirror forms a virtual image of size twice that of the object placed at a distance 5 cm from it.

Find : (a) the focal length of the mirror (b) position of image

Solution 11N.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light
12N.The image formed by a convex mirror is of size one third the size of object. How are u and v related?

Solution 12N.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

13N.The erect image formed by a concave mirror is of size double the size of object. How are u and v related?

Solution 13N.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

14N.The magnification for a mirror is -3. How are u and v related?

Solution 14N.
Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

Selina ICSE Solutions for Class 9 Physics Chapter 7  Reflection of Light

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